Optimal. Leaf size=178 \[ -\frac {\left (a^2+b^2\right )^3}{b^7 d (a+b \tan (c+d x))}-\frac {6 a \left (a^2+b^2\right )^2 \log (a+b \tan (c+d x))}{b^7 d}-\frac {a \left (2 a^2+3 b^2\right ) \tan ^2(c+d x)}{b^5 d}+\frac {\left (a^2+b^2\right ) \tan ^3(c+d x)}{b^4 d}+\frac {\left (5 a^4+9 a^2 b^2+3 b^4\right ) \tan (c+d x)}{b^6 d}-\frac {a \tan ^4(c+d x)}{2 b^3 d}+\frac {\tan ^5(c+d x)}{5 b^2 d} \]
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Rubi [A] time = 0.15, antiderivative size = 178, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {3506, 697} \[ \frac {\left (a^2+b^2\right ) \tan ^3(c+d x)}{b^4 d}-\frac {a \left (2 a^2+3 b^2\right ) \tan ^2(c+d x)}{b^5 d}+\frac {\left (9 a^2 b^2+5 a^4+3 b^4\right ) \tan (c+d x)}{b^6 d}-\frac {\left (a^2+b^2\right )^3}{b^7 d (a+b \tan (c+d x))}-\frac {6 a \left (a^2+b^2\right )^2 \log (a+b \tan (c+d x))}{b^7 d}-\frac {a \tan ^4(c+d x)}{2 b^3 d}+\frac {\tan ^5(c+d x)}{5 b^2 d} \]
Antiderivative was successfully verified.
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Rule 697
Rule 3506
Rubi steps
\begin {align*} \int \frac {\sec ^8(c+d x)}{(a+b \tan (c+d x))^2} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\left (1+\frac {x^2}{b^2}\right )^3}{(a+x)^2} \, dx,x,b \tan (c+d x)\right )}{b d}\\ &=\frac {\operatorname {Subst}\left (\int \left (\frac {5 a^4+9 a^2 b^2+3 b^4}{b^6}-\frac {2 a \left (2 a^2+3 b^2\right ) x}{b^6}+\frac {3 \left (a^2+b^2\right ) x^2}{b^6}-\frac {2 a x^3}{b^6}+\frac {x^4}{b^6}+\frac {\left (a^2+b^2\right )^3}{b^6 (a+x)^2}-\frac {6 a \left (a^2+b^2\right )^2}{b^6 (a+x)}\right ) \, dx,x,b \tan (c+d x)\right )}{b d}\\ &=-\frac {6 a \left (a^2+b^2\right )^2 \log (a+b \tan (c+d x))}{b^7 d}+\frac {\left (5 a^4+9 a^2 b^2+3 b^4\right ) \tan (c+d x)}{b^6 d}-\frac {a \left (2 a^2+3 b^2\right ) \tan ^2(c+d x)}{b^5 d}+\frac {\left (a^2+b^2\right ) \tan ^3(c+d x)}{b^4 d}-\frac {a \tan ^4(c+d x)}{2 b^3 d}+\frac {\tan ^5(c+d x)}{5 b^2 d}-\frac {\left (a^2+b^2\right )^3}{b^7 d (a+b \tan (c+d x))}\\ \end {align*}
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Mathematica [A] time = 2.37, size = 229, normalized size = 1.29 \[ \frac {b^4 \sec ^4(c+d x) \left (a^2-3 a b \tan (c+d x)+4 b^2\right )-2 \left (-2 a^2 b^4 \tan ^4(c+d x)+30 a^2 \left (a^2+b^2\right )^2 \log (a+b \tan (c+d x))+8 \left (a^2+b^2\right )^3+a b^3 \left (5 a^2+7 b^2\right ) \tan ^3(c+d x)-b^2 \left (15 a^4+29 a^2 b^2+8 b^4\right ) \tan ^2(c+d x)+2 a b \tan (c+d x) \left (-11 a^4+15 \left (a^2+b^2\right )^2 \log (a+b \tan (c+d x))-18 a^2 b^2-4 b^4\right )\right )+2 b^6 \sec ^6(c+d x)}{10 b^7 d (a+b \tan (c+d x))} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.86, size = 386, normalized size = 2.17 \[ -\frac {4 \, {\left (15 \, a^{4} b^{2} + 25 \, a^{2} b^{4} + 8 \, b^{6}\right )} \cos \left (d x + c\right )^{6} - 2 \, b^{6} - 2 \, {\left (15 \, a^{4} b^{2} + 25 \, a^{2} b^{4} + 8 \, b^{6}\right )} \cos \left (d x + c\right )^{4} - {\left (5 \, a^{2} b^{4} + 4 \, b^{6}\right )} \cos \left (d x + c\right )^{2} + 30 \, {\left ({\left (a^{6} + 2 \, a^{4} b^{2} + a^{2} b^{4}\right )} \cos \left (d x + c\right )^{6} + {\left (a^{5} b + 2 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{5} \sin \left (d x + c\right )\right )} \log \left (2 \, a b \cos \left (d x + c\right ) \sin \left (d x + c\right ) + {\left (a^{2} - b^{2}\right )} \cos \left (d x + c\right )^{2} + b^{2}\right ) - 30 \, {\left ({\left (a^{6} + 2 \, a^{4} b^{2} + a^{2} b^{4}\right )} \cos \left (d x + c\right )^{6} + {\left (a^{5} b + 2 \, a^{3} b^{3} + a b^{5}\right )} \cos \left (d x + c\right )^{5} \sin \left (d x + c\right )\right )} \log \left (\cos \left (d x + c\right )^{2}\right ) + {\left (3 \, a b^{5} \cos \left (d x + c\right ) - 4 \, {\left (15 \, a^{5} b + 25 \, a^{3} b^{3} + 8 \, a b^{5}\right )} \cos \left (d x + c\right )^{5} + 2 \, {\left (5 \, a^{3} b^{3} + 7 \, a b^{5}\right )} \cos \left (d x + c\right )^{3}\right )} \sin \left (d x + c\right )}{10 \, {\left (a b^{7} d \cos \left (d x + c\right )^{6} + b^{8} d \cos \left (d x + c\right )^{5} \sin \left (d x + c\right )\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 4.96, size = 253, normalized size = 1.42 \[ -\frac {\frac {60 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{b^{7}} - \frac {10 \, {\left (6 \, a^{5} b \tan \left (d x + c\right ) + 12 \, a^{3} b^{3} \tan \left (d x + c\right ) + 6 \, a b^{5} \tan \left (d x + c\right ) + 5 \, a^{6} + 9 \, a^{4} b^{2} + 3 \, a^{2} b^{4} - b^{6}\right )}}{{\left (b \tan \left (d x + c\right ) + a\right )} b^{7}} - \frac {2 \, b^{8} \tan \left (d x + c\right )^{5} - 5 \, a b^{7} \tan \left (d x + c\right )^{4} + 10 \, a^{2} b^{6} \tan \left (d x + c\right )^{3} + 10 \, b^{8} \tan \left (d x + c\right )^{3} - 20 \, a^{3} b^{5} \tan \left (d x + c\right )^{2} - 30 \, a b^{7} \tan \left (d x + c\right )^{2} + 50 \, a^{4} b^{4} \tan \left (d x + c\right ) + 90 \, a^{2} b^{6} \tan \left (d x + c\right ) + 30 \, b^{8} \tan \left (d x + c\right )}{b^{10}}}{10 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.49, size = 305, normalized size = 1.71 \[ \frac {\tan ^{5}\left (d x +c \right )}{5 b^{2} d}-\frac {a \left (\tan ^{4}\left (d x +c \right )\right )}{2 b^{3} d}+\frac {\left (\tan ^{3}\left (d x +c \right )\right ) a^{2}}{d \,b^{4}}+\frac {\tan ^{3}\left (d x +c \right )}{b^{2} d}-\frac {2 a^{3} \left (\tan ^{2}\left (d x +c \right )\right )}{d \,b^{5}}-\frac {3 a \left (\tan ^{2}\left (d x +c \right )\right )}{b^{3} d}+\frac {5 a^{4} \tan \left (d x +c \right )}{d \,b^{6}}+\frac {9 a^{2} \tan \left (d x +c \right )}{d \,b^{4}}+\frac {3 \tan \left (d x +c \right )}{b^{2} d}-\frac {6 a^{5} \ln \left (a +b \tan \left (d x +c \right )\right )}{d \,b^{7}}-\frac {12 a^{3} \ln \left (a +b \tan \left (d x +c \right )\right )}{d \,b^{5}}-\frac {6 a \ln \left (a +b \tan \left (d x +c \right )\right )}{b^{3} d}-\frac {a^{6}}{d \,b^{7} \left (a +b \tan \left (d x +c \right )\right )}-\frac {3 a^{4}}{d \,b^{5} \left (a +b \tan \left (d x +c \right )\right )}-\frac {3 a^{2}}{d \,b^{3} \left (a +b \tan \left (d x +c \right )\right )}-\frac {1}{b d \left (a +b \tan \left (d x +c \right )\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.35, size = 186, normalized size = 1.04 \[ -\frac {\frac {10 \, {\left (a^{6} + 3 \, a^{4} b^{2} + 3 \, a^{2} b^{4} + b^{6}\right )}}{b^{8} \tan \left (d x + c\right ) + a b^{7}} - \frac {2 \, b^{4} \tan \left (d x + c\right )^{5} - 5 \, a b^{3} \tan \left (d x + c\right )^{4} + 10 \, {\left (a^{2} b^{2} + b^{4}\right )} \tan \left (d x + c\right )^{3} - 10 \, {\left (2 \, a^{3} b + 3 \, a b^{3}\right )} \tan \left (d x + c\right )^{2} + 10 \, {\left (5 \, a^{4} + 9 \, a^{2} b^{2} + 3 \, b^{4}\right )} \tan \left (d x + c\right )}{b^{6}} + \frac {60 \, {\left (a^{5} + 2 \, a^{3} b^{2} + a b^{4}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{b^{7}}}{10 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.63, size = 258, normalized size = 1.45 \[ \frac {{\mathrm {tan}\left (c+d\,x\right )}^2\,\left (\frac {a^3}{b^5}-\frac {a\,\left (\frac {3}{b^2}+\frac {3\,a^2}{b^4}\right )}{b}\right )}{d}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^5}{5\,b^2\,d}+\frac {{\mathrm {tan}\left (c+d\,x\right )}^3\,\left (\frac {1}{b^2}+\frac {a^2}{b^4}\right )}{d}-\frac {\mathrm {tan}\left (c+d\,x\right )\,\left (\frac {a^2\,\left (\frac {3}{b^2}+\frac {3\,a^2}{b^4}\right )}{b^2}-\frac {3}{b^2}+\frac {2\,a\,\left (\frac {2\,a^3}{b^5}-\frac {2\,a\,\left (\frac {3}{b^2}+\frac {3\,a^2}{b^4}\right )}{b}\right )}{b}\right )}{d}-\frac {a\,{\mathrm {tan}\left (c+d\,x\right )}^4}{2\,b^3\,d}-\frac {\ln \left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )\,\left (6\,a^5+12\,a^3\,b^2+6\,a\,b^4\right )}{b^7\,d}-\frac {a^6+3\,a^4\,b^2+3\,a^2\,b^4+b^6}{b\,d\,\left (\mathrm {tan}\left (c+d\,x\right )\,b^7+a\,b^6\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sec ^{8}{\left (c + d x \right )}}{\left (a + b \tan {\left (c + d x \right )}\right )^{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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